-3(v+5)=v-4+3(2v+1)

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Solution for -3(v+5)=v-4+3(2v+1) equation: 



-3(v+5)=v-4+3(2v+1)

We move all terms to the left:

-3(v+5)-(v-4+3(2v+1))=0

We multiply parentheses

-3v-(v-4+3(2v+1))-15=0



We calculate terms in parentheses: -(v-4+3(2v+1)), so:

v-4+3(2v+1)

determiningTheFunctionDomain
v+3(2v+1)-4

We multiply parentheses

v+6v+3-4

We add all the numbers together, and all the variables

7v-1

Back to the equation:

-(7v-1)



We get rid of parentheses

-3v-7v+1-15=0

We add all the numbers together, and all the variables

-10v-14=0

We move all terms containing v to the left, all other terms to the right

-10v=14

v=14/-10

v=-1+2/5

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