-3(w+1)+w=4(w+1)-5

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Solution for -3(w+1)+w=4(w+1)-5 equation: 



-3(w+1)+w=4(w+1)-5

We move all terms to the left:

-3(w+1)+w-(4(w+1)-5)=0

We add all the numbers together, and all the variables

w-3(w+1)-(4(w+1)-5)=0

We multiply parentheses

w-3w-(4(w+1)-5)-3=0



We calculate terms in parentheses: -(4(w+1)-5), so:

4(w+1)-5

We multiply parentheses

4w+4-5

We add all the numbers together, and all the variables

4w-1

Back to the equation:

-(4w-1)



We add all the numbers together, and all the variables

-2w-(4w-1)-3=0

We get rid of parentheses

-2w-4w+1-3=0

We add all the numbers together, and all the variables

-6w-2=0

We move all terms containing w to the left, all other terms to the right

-6w=2

w=2/-6

w=-1/3

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