-3(w+2)(-w-2)=0

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Solution for -3(w+2)(-w-2)=0 equation: 



-3(w+2)(-w-2)=0

We add all the numbers together, and all the variables

-3(w+2)(-1w-2)=0

We multiply parentheses ..

-3(-1w^2-2w-2w-4)=0

We multiply parentheses

3w^2+6w+6w+12=0

We add all the numbers together, and all the variables

3w^2+12w+12=0

a = 3; b = 12; c = +12;
Δ = b2-4ac
Δ = 122-4·3·12
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$w=\frac{-b}{2a}=\frac{-12}{6}=-2$

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