-3(w+2)=2w-5+3(3w+1)

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Solution for -3(w+2)=2w-5+3(3w+1) equation: 



-3(w+2)=2w-5+3(3w+1)

We move all terms to the left:

-3(w+2)-(2w-5+3(3w+1))=0

We multiply parentheses

-3w-(2w-5+3(3w+1))-6=0



We calculate terms in parentheses: -(2w-5+3(3w+1)), so:

2w-5+3(3w+1)

determiningTheFunctionDomain
2w+3(3w+1)-5

We multiply parentheses

2w+9w+3-5

We add all the numbers together, and all the variables

11w-2

Back to the equation:

-(11w-2)



We get rid of parentheses

-3w-11w+2-6=0

We add all the numbers together, and all the variables

-14w-4=0

We move all terms containing w to the left, all other terms to the right

-14w=4

w=4/-14

w=-2/7

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