-3(w+2)=5w-7+2(2+w)

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Solution for -3(w+2)=5w-7+2(2+w) equation: 



-3(w+2)=5w-7+2(2+w)

We move all terms to the left:

-3(w+2)-(5w-7+2(2+w))=0

We add all the numbers together, and all the variables

-3(w+2)-(5w-7+2(w+2))=0

We multiply parentheses

-3w-(5w-7+2(w+2))-6=0



We calculate terms in parentheses: -(5w-7+2(w+2)), so:

5w-7+2(w+2)

determiningTheFunctionDomain
5w+2(w+2)-7

We multiply parentheses

5w+2w+4-7

We add all the numbers together, and all the variables

7w-3

Back to the equation:

-(7w-3)



We get rid of parentheses

-3w-7w+3-6=0

We add all the numbers together, and all the variables

-10w-3=0

We move all terms containing w to the left, all other terms to the right

-10w=3

w=3/-10

w=-3/10

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