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-3(x+1)=3x-5+2(2x+8)
We move all terms to the left:
-3(x+1)-(3x-5+2(2x+8))=0
We multiply parentheses
-3x-(3x-5+2(2x+8))-3=0
We calculate terms in parentheses: -(3x-5+2(2x+8)), so:We get rid of parentheses
3x-5+2(2x+8)
determiningTheFunctionDomain 3x+2(2x+8)-5
We multiply parentheses
3x+4x+16-5
We add all the numbers together, and all the variables
7x+11
Back to the equation:
-(7x+11)
-3x-7x-11-3=0
We add all the numbers together, and all the variables
-10x-14=0
We move all terms containing x to the left, all other terms to the right
-10x=14
x=14/-10
x=-1+2/5
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