-3(x+2)+4(3x-8)=2(x+4)+2(6x-3)

Solution for -3(x+2)+4(3x-8)=2(x+4)+2(6x-3) equation:

-3(x+2)+4(3x-8)=2(x+4)+2(6x-3)

We move all terms to the left:

-3(x+2)+4(3x-8)-(2(x+4)+2(6x-3))=0

We multiply parentheses

-3x+12x-(2(x+4)+2(6x-3))-6-32=0


We calculate terms in parentheses: -(2(x+4)+2(6x-3)), so:

2(x+4)+2(6x-3)

We multiply parentheses

2x+12x+8-6

We add all the numbers together, and all the variables

14x+2

Back to the equation:

-(14x+2)


We add all the numbers together, and all the variables

9x-(14x+2)-38=0

We get rid of parentheses

9x-14x-2-38=0

We add all the numbers together, and all the variables

-5x-40=0

We move all terms containing x to the left, all other terms to the right

-5x=40

x=40/-5

x=-8