-3(x+2)+4(x-4)=

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Solution for -3(x+2)+4(x-4)= equation:


Simplifying
-3(x + 2) + 4(x + -4) = 0

Reorder the terms:
-3(2 + x) + 4(x + -4) = 0
(2 * -3 + x * -3) + 4(x + -4) = 0
(-6 + -3x) + 4(x + -4) = 0

Reorder the terms:
-6 + -3x + 4(-4 + x) = 0
-6 + -3x + (-4 * 4 + x * 4) = 0
-6 + -3x + (-16 + 4x) = 0

Reorder the terms:
-6 + -16 + -3x + 4x = 0

Combine like terms: -6 + -16 = -22
-22 + -3x + 4x = 0

Combine like terms: -3x + 4x = 1x
-22 + 1x = 0

Solving
-22 + 1x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '22' to each side of the equation.
-22 + 22 + 1x = 0 + 22

Combine like terms: -22 + 22 = 0
0 + 1x = 0 + 22
1x = 0 + 22

Combine like terms: 0 + 22 = 22
1x = 22

Divide each side by '1'.
x = 22

Simplifying
x = 22

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