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-3(x+2)=-3(x+1)-3
We move all terms to the left:
-3(x+2)-(-3(x+1)-3)=0
We multiply parentheses
-3x-(-3(x+1)-3)-6=0
We calculate terms in parentheses: -(-3(x+1)-3), so:We get rid of parentheses
-3(x+1)-3
We multiply parentheses
-3x-3-3
We add all the numbers together, and all the variables
-3x-6
Back to the equation:
-(-3x-6)
-3x+3x+6-6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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