-3(x+2)=2(3x-2)-2

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Solution for -3(x+2)=2(3x-2)-2 equation: 



-3(x+2)=2(3x-2)-2

We move all terms to the left:

-3(x+2)-(2(3x-2)-2)=0

We multiply parentheses

-3x-(2(3x-2)-2)-6=0



We calculate terms in parentheses: -(2(3x-2)-2), so:

2(3x-2)-2

We multiply parentheses

6x-4-2

We add all the numbers together, and all the variables

6x-6

Back to the equation:

-(6x-6)



We get rid of parentheses

-3x-6x+6-6=0

We add all the numbers together, and all the variables

-9x=0

x=0/-9

x=0

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