-3(x+2)=3(2x-2)+5

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Solution for -3(x+2)=3(2x-2)+5 equation: 



-3(x+2)=3(2x-2)+5

We move all terms to the left:

-3(x+2)-(3(2x-2)+5)=0

We multiply parentheses

-3x-(3(2x-2)+5)-6=0



We calculate terms in parentheses: -(3(2x-2)+5), so:

3(2x-2)+5

We multiply parentheses

6x-6+5

We add all the numbers together, and all the variables

6x-1

Back to the equation:

-(6x-1)



We get rid of parentheses

-3x-6x+1-6=0

We add all the numbers together, and all the variables

-9x-5=0

We move all terms containing x to the left, all other terms to the right

-9x=5

x=5/-9

x=-5/9

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