-3(x+3)+4x=4(x+1)-5

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Solution for -3(x+3)+4x=4(x+1)-5 equation: 



-3(x+3)+4x=4(x+1)-5

We move all terms to the left:

-3(x+3)+4x-(4(x+1)-5)=0

We add all the numbers together, and all the variables

4x-3(x+3)-(4(x+1)-5)=0

We multiply parentheses

4x-3x-(4(x+1)-5)-9=0



We calculate terms in parentheses: -(4(x+1)-5), so:

4(x+1)-5

We multiply parentheses

4x+4-5

We add all the numbers together, and all the variables

4x-1

Back to the equation:

-(4x-1)



We add all the numbers together, and all the variables

x-(4x-1)-9=0

We get rid of parentheses

x-4x+1-9=0

We add all the numbers together, and all the variables

-3x-8=0

We move all terms containing x to the left, all other terms to the right

-3x=8

x=8/-3

x=-2+2/3

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