-3(x+3)-x-2=-4(x+4)+5

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Solution for -3(x+3)-x-2=-4(x+4)+5 equation: 



-3(x+3)-x-2=-4(x+4)+5

We move all terms to the left:

-3(x+3)-x-2-(-4(x+4)+5)=0

We add all the numbers together, and all the variables

-1x-3(x+3)-(-4(x+4)+5)-2=0

We multiply parentheses

-1x-3x-(-4(x+4)+5)-9-2=0



We calculate terms in parentheses: -(-4(x+4)+5), so:

-4(x+4)+5

We multiply parentheses

-4x-16+5

We add all the numbers together, and all the variables

-4x-11

Back to the equation:

-(-4x-11)



We add all the numbers together, and all the variables

-4x-(-4x-11)-11=0

We get rid of parentheses

-4x+4x+11-11=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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