-3(x+3)=19+x

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Solution for -3(x+3)=19+x equation: 



-3(x+3)=19+x

We move all terms to the left:

-3(x+3)-(19+x)=0

We add all the numbers together, and all the variables

-3(x+3)-(x+19)=0

We multiply parentheses

-3x-(x+19)-9=0

We get rid of parentheses

-3x-x-19-9=0

We add all the numbers together, and all the variables

-4x-28=0

We move all terms containing x to the left, all other terms to the right

-4x=28

x=28/-4

x=-7

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