-3(x+5)=(1/3)(2x-10)

Solution for -3(x+5)=(1/3)(2x-10) equation:

-3(x+5)=(1/3)(2x-10)

We move all terms to the left:

-3(x+5)-((1/3)(2x-10))=0


Domain of the equation: 3)(2x-10))!=0

x∈R


We add all the numbers together, and all the variables

-3(x+5)-((+1/3)(2x-10))=0

We multiply parentheses

-3x-((+1/3)(2x-10))-15=0

We multiply parentheses ..

-((+2x^2+1/3*-10))-3x-15=0

We multiply all the terms by the denominator


-((+2x^2+1-3x*3*-10))-15*3*-10))=0


We calculate terms in parentheses: -((+2x^2+1-3x*3*-10)), so:

(+2x^2+1-3x*3*-10)

We get rid of parentheses

2x^2-3x*3*+1-10

We add all the numbers together, and all the variables

2x^2-3x*3*-9

Wy multiply elements

2x^2-9x^2-9

We add all the numbers together, and all the variables

-7x^2-9

Back to the equation:

-(-7x^2-9)


We add all the numbers together, and all the variables

-(-7x^2-9)=0

We get rid of parentheses

7x^2+9=0

a = 7; b = 0; c = +9;
Δ = b2-4ac
Δ = 02-4·7·9
Δ = -252
Delta is less than zero, so there is no solution for the equation