-3(x-1)+8x(x-3)=6x+7-5x

Solution for -3(x-1)+8x(x-3)=6x+7-5x equation:

-3(x-1)+8x(x-3)=6x+7-5x

We move all terms to the left:

-3(x-1)+8x(x-3)-(6x+7-5x)=0

We add all the numbers together, and all the variables

-3(x-1)+8x(x-3)-(x+7)=0

We multiply parentheses

8x^2-3x-24x-(x+7)+3=0

We get rid of parentheses

8x^2-3x-24x-x-7+3=0

We add all the numbers together, and all the variables

8x^2-28x-4=0

a = 8; b = -28; c = -4;
Δ = b2-4ac
Δ = -282-4·8·(-4)
Δ = 912
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{912}=\sqrt{16*57}=\sqrt{16}*\sqrt{57}=4\sqrt{57}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-4\sqrt{57}}{2*8}=\frac{28-4\sqrt{57}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+4\sqrt{57}}{2*8}=\frac{28+4\sqrt{57}}{16}
$