-3(x-2)+10=2(5-x)+20

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Solution for -3(x-2)+10=2(5-x)+20 equation: 



-3(x-2)+10=2(5-x)+20

We move all terms to the left:

-3(x-2)+10-(2(5-x)+20)=0

We add all the numbers together, and all the variables

-3(x-2)-(2(-1x+5)+20)+10=0

We multiply parentheses

-3x-(2(-1x+5)+20)+6+10=0



We calculate terms in parentheses: -(2(-1x+5)+20), so:

2(-1x+5)+20

We multiply parentheses

-2x+10+20

We add all the numbers together, and all the variables

-2x+30

Back to the equation:

-(-2x+30)



We add all the numbers together, and all the variables

-3x-(-2x+30)+16=0

We get rid of parentheses

-3x+2x-30+16=0

We add all the numbers together, and all the variables

-1x-14=0

We move all terms containing x to the left, all other terms to the right

-x=14

x=14/-1

x=-14

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