-3(x-2)-(x+4)=-8(x+2)+5(x-4)

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Solution for -3(x-2)-(x+4)=-8(x+2)+5(x-4) equation: 



-3(x-2)-(x+4)=-8(x+2)+5(x-4)

We move all terms to the left:

-3(x-2)-(x+4)-(-8(x+2)+5(x-4))=0

We multiply parentheses

-3x-(x+4)-(-8(x+2)+5(x-4))+6=0

We get rid of parentheses

-3x-x-(-8(x+2)+5(x-4))-4+6=0



We calculate terms in parentheses: -(-8(x+2)+5(x-4)), so:

-8(x+2)+5(x-4)

We multiply parentheses

-8x+5x-16-20

We add all the numbers together, and all the variables

-3x-36

Back to the equation:

-(-3x-36)



We add all the numbers together, and all the variables

-4x-(-3x-36)+2=0

We get rid of parentheses

-4x+3x+36+2=0

We add all the numbers together, and all the variables

-1x+38=0

We move all terms containing x to the left, all other terms to the right

-x=-38

x=-38/-1

x=+38

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