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-3(x-2)-5=5-(2x+1)
We move all terms to the left:
-3(x-2)-5-(5-(2x+1))=0
We multiply parentheses
-3x-(5-(2x+1))+6-5=0
We calculate terms in parentheses: -(5-(2x+1)), so:We add all the numbers together, and all the variables
5-(2x+1)
determiningTheFunctionDomain -(2x+1)+5
We get rid of parentheses
-2x-1+5
We add all the numbers together, and all the variables
-2x+4
Back to the equation:
-(-2x+4)
-3x-(-2x+4)+1=0
We get rid of parentheses
-3x+2x-4+1=0
We add all the numbers together, and all the variables
-1x-3=0
We move all terms containing x to the left, all other terms to the right
-x=3
x=3/-1
x=-3
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