-3(x-2)=3(x-3)-x

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Solution for -3(x-2)=3(x-3)-x equation: 



-3(x-2)=3(x-3)-x

We move all terms to the left:

-3(x-2)-(3(x-3)-x)=0

We multiply parentheses

-3x-(3(x-3)-x)+6=0



We calculate terms in parentheses: -(3(x-3)-x), so:

3(x-3)-x

We add all the numbers together, and all the variables

-1x+3(x-3)

We multiply parentheses

-1x+3x-9

We add all the numbers together, and all the variables

2x-9

Back to the equation:

-(2x-9)



We get rid of parentheses

-3x-2x+9+6=0

We add all the numbers together, and all the variables

-5x+15=0

We move all terms containing x to the left, all other terms to the right

-5x=-15

x=-15/-5

x=+3

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