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-3(x-3)-26=2x-5(x+1)
We move all terms to the left:
-3(x-3)-26-(2x-5(x+1))=0
We multiply parentheses
-3x-(2x-5(x+1))+9-26=0
We calculate terms in parentheses: -(2x-5(x+1)), so:We add all the numbers together, and all the variables
2x-5(x+1)
We multiply parentheses
2x-5x-5
We add all the numbers together, and all the variables
-3x-5
Back to the equation:
-(-3x-5)
-3x-(-3x-5)-17=0
We get rid of parentheses
-3x+3x+5-17=0
We add all the numbers together, and all the variables
-12!=0
There is no solution for this equation
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