-3(x-4)+2(3x+2)+8=-12

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Solution for -3(x-4)+2(3x+2)+8=-12 equation: 



-3(x-4)+2(3x+2)+8=-12

We move all terms to the left:

-3(x-4)+2(3x+2)+8-(-12)=0

We add all the numbers together, and all the variables

-3(x-4)+2(3x+2)+20=0

We multiply parentheses

-3x+6x+12+4+20=0

We add all the numbers together, and all the variables

3x+36=0

We move all terms containing x to the left, all other terms to the right

3x=-36

x=-36/3

x=-12

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