-3(x-4)+3=9x+2(x+1)

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Solution for -3(x-4)+3=9x+2(x+1) equation: 



-3(x-4)+3=9x+2(x+1)

We move all terms to the left:

-3(x-4)+3-(9x+2(x+1))=0

We multiply parentheses

-3x-(9x+2(x+1))+12+3=0



We calculate terms in parentheses: -(9x+2(x+1)), so:

9x+2(x+1)

We multiply parentheses

9x+2x+2

We add all the numbers together, and all the variables

11x+2

Back to the equation:

-(11x+2)



We add all the numbers together, and all the variables

-3x-(11x+2)+15=0

We get rid of parentheses

-3x-11x-2+15=0

We add all the numbers together, and all the variables

-14x+13=0

We move all terms containing x to the left, all other terms to the right

-14x=-13

x=-13/-14

x=13/14

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