-3(x-4)+x=16-x

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Solution for -3(x-4)+x=16-x equation: 



-3(x-4)+x=16-x

We move all terms to the left:

-3(x-4)+x-(16-x)=0

We add all the numbers together, and all the variables

-3(x-4)+x-(-1x+16)=0

We add all the numbers together, and all the variables

x-3(x-4)-(-1x+16)=0

We multiply parentheses

x-3x-(-1x+16)+12=0

We get rid of parentheses

x-3x+1x-16+12=0

We add all the numbers together, and all the variables

-1x-4=0

We move all terms containing x to the left, all other terms to the right

-x=4

x=4/-1

x=-4

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