-3(x-4)+x=4x-12

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Solution for -3(x-4)+x=4x-12 equation: 



-3(x-4)+x=4x-12

We move all terms to the left:

-3(x-4)+x-(4x-12)=0

We add all the numbers together, and all the variables

x-3(x-4)-(4x-12)=0

We multiply parentheses

x-3x-(4x-12)+12=0

We get rid of parentheses

x-3x-4x+12+12=0

We add all the numbers together, and all the variables

-6x+24=0

We move all terms containing x to the left, all other terms to the right

-6x=-24

x=-24/-6

x=+4

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