-3(x-4)-(x-4)=2(-4x+3)+1

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Solution for -3(x-4)-(x-4)=2(-4x+3)+1 equation: 



-3(x-4)-(x-4)=2(-4x+3)+1

We move all terms to the left:

-3(x-4)-(x-4)-(2(-4x+3)+1)=0

We multiply parentheses

-3x-(x-4)-(2(-4x+3)+1)+12=0

We get rid of parentheses

-3x-x-(2(-4x+3)+1)+4+12=0



We calculate terms in parentheses: -(2(-4x+3)+1), so:

2(-4x+3)+1

We multiply parentheses

-8x+6+1

We add all the numbers together, and all the variables

-8x+7

Back to the equation:

-(-8x+7)



We add all the numbers together, and all the variables

-4x-(-8x+7)+16=0

We get rid of parentheses

-4x+8x-7+16=0

We add all the numbers together, and all the variables

4x+9=0

We move all terms containing x to the left, all other terms to the right

4x=-9

x=-9/4

x=-2+1/4

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