-3(x-4)-2x-8=9(x+2)+1

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Solution for -3(x-4)-2x-8=9(x+2)+1 equation: 



-3(x-4)-2x-8=9(x+2)+1

We move all terms to the left:

-3(x-4)-2x-8-(9(x+2)+1)=0

We add all the numbers together, and all the variables

-2x-3(x-4)-(9(x+2)+1)-8=0

We multiply parentheses

-2x-3x-(9(x+2)+1)+12-8=0



We calculate terms in parentheses: -(9(x+2)+1), so:

9(x+2)+1

We multiply parentheses

9x+18+1

We add all the numbers together, and all the variables

9x+19

Back to the equation:

-(9x+19)



We add all the numbers together, and all the variables

-5x-(9x+19)+4=0

We get rid of parentheses

-5x-9x-19+4=0

We add all the numbers together, and all the variables

-14x-15=0

We move all terms containing x to the left, all other terms to the right

-14x=15

x=15/-14

x=-1+1/14

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