-3(x-4)=3x+12

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Solution for -3(x-4)=3x+12 equation: 



-3(x-4)=3x+12

We move all terms to the left:

-3(x-4)-(3x+12)=0

We multiply parentheses

-3x-(3x+12)+12=0

We get rid of parentheses

-3x-3x-12+12=0

We add all the numbers together, and all the variables

-6x=0

x=0/-6

x=0

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