-3(x-4)=3x+12

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Solution for -3(x-4)=3x+12 equation:



-3(x-4)=3x+12
We move all terms to the left:
-3(x-4)-(3x+12)=0
We multiply parentheses
-3x-(3x+12)+12=0
We get rid of parentheses
-3x-3x-12+12=0
We add all the numbers together, and all the variables
-6x=0
x=0/-6
x=0

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