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-3(x-5)+-2x=40
We move all terms to the left:
-3(x-5)+-2x-(40)=0
determiningTheFunctionDomain -3(x-5)-2x-40+=0
We add all the numbers together, and all the variables
-2x-3(x-5)=0
We multiply parentheses
-2x-3x+15=0
We add all the numbers together, and all the variables
-5x+15=0
We move all terms containing x to the left, all other terms to the right
-5x=-15
x=-15/-5
x=+3
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