-3(x-5)+3x=3(2x-1)

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Solution for -3(x-5)+3x=3(2x-1) equation: 



-3(x-5)+3x=3(2x-1)

We move all terms to the left:

-3(x-5)+3x-(3(2x-1))=0

We add all the numbers together, and all the variables

3x-3(x-5)-(3(2x-1))=0

We multiply parentheses

3x-3x-(3(2x-1))+15=0



We calculate terms in parentheses: -(3(2x-1)), so:

3(2x-1)

We multiply parentheses

6x-3

Back to the equation:

-(6x-3)



We add all the numbers together, and all the variables

-(6x-3)+15=0

We get rid of parentheses

-6x+3+15=0

We add all the numbers together, and all the variables

-6x+18=0

We move all terms containing x to the left, all other terms to the right

-6x=-18

x=-18/-6

x=+3

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