-3(x-6)+1=2(x-2)+48;x=-5

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Solution for -3(x-6)+1=2(x-2)+48;x=-5 equation:



-3(x-6)+1=2(x-2)+48x=-5
We move all terms to the left:
-3(x-6)+1-(2(x-2)+48x)=0
We multiply parentheses
-3x-(2(x-2)+48x)+18+1=0
We calculate terms in parentheses: -(2(x-2)+48x), so:
2(x-2)+48x
We add all the numbers together, and all the variables
48x+2(x-2)
We multiply parentheses
48x+2x-4
We add all the numbers together, and all the variables
50x-4
Back to the equation:
-(50x-4)
We add all the numbers together, and all the variables
-3x-(50x-4)+19=0
We get rid of parentheses
-3x-50x+4+19=0
We add all the numbers together, and all the variables
-53x+23=0
We move all terms containing x to the left, all other terms to the right
-53x=-23
x=-23/-53
x=23/53

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