-3(x-7)(x+1)=0

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Solution for -3(x-7)(x+1)=0 equation:



-3(x-7)(x+1)=0
We multiply parentheses ..
-3(+x^2+x-7x-7)=0
We multiply parentheses
-3x^2-3x+21x+21=0
We add all the numbers together, and all the variables
-3x^2+18x+21=0
a = -3; b = 18; c = +21;
Δ = b2-4ac
Δ = 182-4·(-3)·21
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-24}{2*-3}=\frac{-42}{-6} =+7 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+24}{2*-3}=\frac{6}{-6} =-1 $

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