-3(x=2)-3x2x+18

Solution for -3(x=2)-3x2x+18 equation:

-3(x=2)-3x^2x+18

We move all terms to the left:

-3(x-(2)-3x^2x+18)=0

We multiply parentheses

9x^2-3x+6-54=0

We add all the numbers together, and all the variables

9x^2-3x-48=0

a = 9; b = -3; c = -48;
Δ = b2-4ac
Δ = -32-4·9·(-48)
Δ = 1737
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1737}=\sqrt{9*193}=\sqrt{9}*\sqrt{193}=3\sqrt{193}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3\sqrt{193}}{2*9}=\frac{3-3\sqrt{193}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3\sqrt{193}}{2*9}=\frac{3+3\sqrt{193}}{18}
$