-3(y+1)+3(3y-5)=5(y-3)+8

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Solution for -3(y+1)+3(3y-5)=5(y-3)+8 equation:



-3(y+1)+3(3y-5)=5(y-3)+8
We move all terms to the left:
-3(y+1)+3(3y-5)-(5(y-3)+8)=0
We multiply parentheses
-3y+9y-(5(y-3)+8)-3-15=0
We calculate terms in parentheses: -(5(y-3)+8), so:
5(y-3)+8
We multiply parentheses
5y-15+8
We add all the numbers together, and all the variables
5y-7
Back to the equation:
-(5y-7)
We add all the numbers together, and all the variables
6y-(5y-7)-18=0
We get rid of parentheses
6y-5y+7-18=0
We add all the numbers together, and all the variables
y-11=0
We move all terms containing y to the left, all other terms to the right
y=11

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