-3(y+1)+7y=4(y+1)-5

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Solution for -3(y+1)+7y=4(y+1)-5 equation: 


Simplifying
-3(y + 1) + 7y = 4(y + 1) + -5

Reorder the terms:
-3(1 + y) + 7y = 4(y + 1) + -5
(1 * -3 + y * -3) + 7y = 4(y + 1) + -5
(-3 + -3y) + 7y = 4(y + 1) + -5

Combine like terms: -3y + 7y = 4y
-3 + 4y = 4(y + 1) + -5

Reorder the terms:
-3 + 4y = 4(1 + y) + -5
-3 + 4y = (1 * 4 + y * 4) + -5
-3 + 4y = (4 + 4y) + -5

Reorder the terms:
-3 + 4y = 4 + -5 + 4y

Combine like terms: 4 + -5 = -1
-3 + 4y = -1 + 4y

Add '-4y' to each side of the equation.
-3 + 4y + -4y = -1 + 4y + -4y

Combine like terms: 4y + -4y = 0
-3 + 0 = -1 + 4y + -4y
-3 = -1 + 4y + -4y

Combine like terms: 4y + -4y = 0
-3 = -1 + 0
-3 = -1

Solving
-3 = -1

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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