-3(y+1)+7y=4(y+1)-7

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Solution for -3(y+1)+7y=4(y+1)-7 equation:


Simplifying
-3(y + 1) + 7y = 4(y + 1) + -7

Reorder the terms:
-3(1 + y) + 7y = 4(y + 1) + -7
(1 * -3 + y * -3) + 7y = 4(y + 1) + -7
(-3 + -3y) + 7y = 4(y + 1) + -7

Combine like terms: -3y + 7y = 4y
-3 + 4y = 4(y + 1) + -7

Reorder the terms:
-3 + 4y = 4(1 + y) + -7
-3 + 4y = (1 * 4 + y * 4) + -7
-3 + 4y = (4 + 4y) + -7

Reorder the terms:
-3 + 4y = 4 + -7 + 4y

Combine like terms: 4 + -7 = -3
-3 + 4y = -3 + 4y

Add '3' to each side of the equation.
-3 + 3 + 4y = -3 + 3 + 4y

Combine like terms: -3 + 3 = 0
0 + 4y = -3 + 3 + 4y
4y = -3 + 3 + 4y

Combine like terms: -3 + 3 = 0
4y = 0 + 4y
4y = 4y

Add '-4y' to each side of the equation.
4y + -4y = 4y + -4y

Combine like terms: 4y + -4y = 0
0 = 4y + -4y

Combine like terms: 4y + -4y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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