-3(y+1)=3y-1+2(5y+5)

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Solution for -3(y+1)=3y-1+2(5y+5) equation: 



-3(y+1)=3y-1+2(5y+5)

We move all terms to the left:

-3(y+1)-(3y-1+2(5y+5))=0

We multiply parentheses

-3y-(3y-1+2(5y+5))-3=0



We calculate terms in parentheses: -(3y-1+2(5y+5)), so:

3y-1+2(5y+5)

determiningTheFunctionDomain
3y+2(5y+5)-1

We multiply parentheses

3y+10y+10-1

We add all the numbers together, and all the variables

13y+9

Back to the equation:

-(13y+9)



We get rid of parentheses

-3y-13y-9-3=0

We add all the numbers together, and all the variables

-16y-12=0

We move all terms containing y to the left, all other terms to the right

-16y=12

y=12/-16

y=-3/4

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