-3(y+1)=3y-5+4(2y+1)

Solution for -3(y+1)=3y-5+4(2y+1) equation:

-3(y+1)=3y-5+4(2y+1)

We move all terms to the left:

-3(y+1)-(3y-5+4(2y+1))=0

We multiply parentheses

-3y-(3y-5+4(2y+1))-3=0


We calculate terms in parentheses: -(3y-5+4(2y+1)), so:

3y-5+4(2y+1)

determiningTheFunctionDomain
3y+4(2y+1)-5

We multiply parentheses

3y+8y+4-5

We add all the numbers together, and all the variables

11y-1

Back to the equation:

-(11y-1)


We get rid of parentheses

-3y-11y+1-3=0

We add all the numbers together, and all the variables

-14y-2=0

We move all terms containing y to the left, all other terms to the right

-14y=2

y=2/-14

y=-1/7