-3(y+1)=5y-7+2(3y+5)

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Solution for -3(y+1)=5y-7+2(3y+5) equation: 



-3(y+1)=5y-7+2(3y+5)

We move all terms to the left:

-3(y+1)-(5y-7+2(3y+5))=0

We multiply parentheses

-3y-(5y-7+2(3y+5))-3=0



We calculate terms in parentheses: -(5y-7+2(3y+5)), so:

5y-7+2(3y+5)

determiningTheFunctionDomain
5y+2(3y+5)-7

We multiply parentheses

5y+6y+10-7

We add all the numbers together, and all the variables

11y+3

Back to the equation:

-(11y+3)



We get rid of parentheses

-3y-11y-3-3=0

We add all the numbers together, and all the variables

-14y-6=0

We move all terms containing y to the left, all other terms to the right

-14y=6

y=6/-14

y=-3/7

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