-3(y+1)=7y-3+2(4y+7)

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Solution for -3(y+1)=7y-3+2(4y+7) equation: 



-3(y+1)=7y-3+2(4y+7)

We move all terms to the left:

-3(y+1)-(7y-3+2(4y+7))=0

We multiply parentheses

-3y-(7y-3+2(4y+7))-3=0



We calculate terms in parentheses: -(7y-3+2(4y+7)), so:

7y-3+2(4y+7)

determiningTheFunctionDomain
7y+2(4y+7)-3

We multiply parentheses

7y+8y+14-3

We add all the numbers together, and all the variables

15y+11

Back to the equation:

-(15y+11)



We get rid of parentheses

-3y-15y-11-3=0

We add all the numbers together, and all the variables

-18y-14=0

We move all terms containing y to the left, all other terms to the right

-18y=14

y=14/-18

y=-7/9

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