-3(y+2)+5(y-4)=2(2y-10)

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Solution for -3(y+2)+5(y-4)=2(2y-10) equation: 



-3(y+2)+5(y-4)=2(2y-10)

We move all terms to the left:

-3(y+2)+5(y-4)-(2(2y-10))=0

We multiply parentheses

-3y+5y-(2(2y-10))-6-20=0



We calculate terms in parentheses: -(2(2y-10)), so:

2(2y-10)

We multiply parentheses

4y-20

Back to the equation:

-(4y-20)



We add all the numbers together, and all the variables

2y-(4y-20)-26=0

We get rid of parentheses

2y-4y+20-26=0

We add all the numbers together, and all the variables

-2y-6=0

We move all terms containing y to the left, all other terms to the right

-2y=6

y=6/-2

y=-3

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