-3(y+2)-8y=2(y-3)-7

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Solution for -3(y+2)-8y=2(y-3)-7 equation: 



-3(y+2)-8y=2(y-3)-7

We move all terms to the left:

-3(y+2)-8y-(2(y-3)-7)=0

We add all the numbers together, and all the variables

-8y-3(y+2)-(2(y-3)-7)=0

We multiply parentheses

-8y-3y-(2(y-3)-7)-6=0



We calculate terms in parentheses: -(2(y-3)-7), so:

2(y-3)-7

We multiply parentheses

2y-6-7

We add all the numbers together, and all the variables

2y-13

Back to the equation:

-(2y-13)



We add all the numbers together, and all the variables

-11y-(2y-13)-6=0

We get rid of parentheses

-11y-2y+13-6=0

We add all the numbers together, and all the variables

-13y+7=0

We move all terms containing y to the left, all other terms to the right

-13y=-7

y=-7/-13

y=7/13

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