-3(y+2)-y=2(y-1)=5

Solution for -3(y+2)-y=2(y-1)=5 equation:

-3(y+2)-y=2(y-1)=5

We move all terms to the left:

-3(y+2)-y-(2(y-1))=0

We add all the numbers together, and all the variables

-1y-3(y+2)-(2(y-1))=0

We multiply parentheses

-1y-3y-(2(y-1))-6=0


We calculate terms in parentheses: -(2(y-1)), so:

2(y-1)

We multiply parentheses

2y-2

Back to the equation:

-(2y-2)


We add all the numbers together, and all the variables

-4y-(2y-2)-6=0

We get rid of parentheses

-4y-2y+2-6=0

We add all the numbers together, and all the variables

-6y-4=0

We move all terms containing y to the left, all other terms to the right

-6y=4

y=4/-6

y=-2/3