-3(y+2)=-2(y+4)-y

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Solution for -3(y+2)=-2(y+4)-y equation: 


Simplifying
-3(y + 2) = -2(y + 4) + -1y

Reorder the terms:
-3(2 + y) = -2(y + 4) + -1y
(2 * -3 + y * -3) = -2(y + 4) + -1y
(-6 + -3y) = -2(y + 4) + -1y

Reorder the terms:
-6 + -3y = -2(4 + y) + -1y
-6 + -3y = (4 * -2 + y * -2) + -1y
-6 + -3y = (-8 + -2y) + -1y

Combine like terms: -2y + -1y = -3y
-6 + -3y = -8 + -3y

Add '3y' to each side of the equation.
-6 + -3y + 3y = -8 + -3y + 3y

Combine like terms: -3y + 3y = 0
-6 + 0 = -8 + -3y + 3y
-6 = -8 + -3y + 3y

Combine like terms: -3y + 3y = 0
-6 = -8 + 0
-6 = -8

Solving
-6 = -8

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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