-3(y+2)=3y-1+2(6y+5)

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Solution for -3(y+2)=3y-1+2(6y+5) equation: 



-3(y+2)=3y-1+2(6y+5)

We move all terms to the left:

-3(y+2)-(3y-1+2(6y+5))=0

We multiply parentheses

-3y-(3y-1+2(6y+5))-6=0



We calculate terms in parentheses: -(3y-1+2(6y+5)), so:

3y-1+2(6y+5)

determiningTheFunctionDomain
3y+2(6y+5)-1

We multiply parentheses

3y+12y+10-1

We add all the numbers together, and all the variables

15y+9

Back to the equation:

-(15y+9)



We get rid of parentheses

-3y-15y-9-6=0

We add all the numbers together, and all the variables

-18y-15=0

We move all terms containing y to the left, all other terms to the right

-18y=15

y=15/-18

y=-5/6

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