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-3(y+2)=3y-8+3(2y+2)
We move all terms to the left:
-3(y+2)-(3y-8+3(2y+2))=0
We multiply parentheses
-3y-(3y-8+3(2y+2))-6=0
We calculate terms in parentheses: -(3y-8+3(2y+2)), so:We get rid of parentheses
3y-8+3(2y+2)
determiningTheFunctionDomain 3y+3(2y+2)-8
We multiply parentheses
3y+6y+6-8
We add all the numbers together, and all the variables
9y-2
Back to the equation:
-(9y-2)
-3y-9y+2-6=0
We add all the numbers together, and all the variables
-12y-4=0
We move all terms containing y to the left, all other terms to the right
-12y=4
y=4/-12
y=-1/3
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