-3(y+2)=y-4+4(3y+3)

Solution for -3(y+2)=y-4+4(3y+3) equation:

-3(y+2)=y-4+4(3y+3)

We move all terms to the left:

-3(y+2)-(y-4+4(3y+3))=0

We multiply parentheses

-3y-(y-4+4(3y+3))-6=0


We calculate terms in parentheses: -(y-4+4(3y+3)), so:

y-4+4(3y+3)

determiningTheFunctionDomain
y+4(3y+3)-4

We multiply parentheses

y+12y+12-4

We add all the numbers together, and all the variables

13y+8

Back to the equation:

-(13y+8)


We get rid of parentheses

-3y-13y-8-6=0

We add all the numbers together, and all the variables

-16y-14=0

We move all terms containing y to the left, all other terms to the right

-16y=14

y=14/-16

y=-7/8