-3(y+3)+3(3y-7)=5(y-5)+14

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Solution for -3(y+3)+3(3y-7)=5(y-5)+14 equation: 



-3(y+3)+3(3y-7)=5(y-5)+14

We move all terms to the left:

-3(y+3)+3(3y-7)-(5(y-5)+14)=0

We multiply parentheses

-3y+9y-(5(y-5)+14)-9-21=0



We calculate terms in parentheses: -(5(y-5)+14), so:

5(y-5)+14

We multiply parentheses

5y-25+14

We add all the numbers together, and all the variables

5y-11

Back to the equation:

-(5y-11)



We add all the numbers together, and all the variables

6y-(5y-11)-30=0

We get rid of parentheses

6y-5y+11-30=0

We add all the numbers together, and all the variables

y-19=0

We move all terms containing y to the left, all other terms to the right

y=19

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