-3(y+3)=-6y-12

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Solution for -3(y+3)=-6y-12 equation: 



-3(y+3)=-6y-12

We move all terms to the left:

-3(y+3)-(-6y-12)=0

We multiply parentheses

-3y-(-6y-12)-9=0

We get rid of parentheses

-3y+6y+12-9=0

We add all the numbers together, and all the variables

3y+3=0

We move all terms containing y to the left, all other terms to the right

3y=-3

y=-3/3

y=-1

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