-3(y+3)=3y+39

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Solution for -3(y+3)=3y+39 equation: 



-3(y+3)=3y+39

We move all terms to the left:

-3(y+3)-(3y+39)=0

We multiply parentheses

-3y-(3y+39)-9=0

We get rid of parentheses

-3y-3y-39-9=0

We add all the numbers together, and all the variables

-6y-48=0

We move all terms containing y to the left, all other terms to the right

-6y=48

y=48/-6

y=-8

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